Optimal. Leaf size=172 \[ \frac{i b \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{i b \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{2 i \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{c^5 d}+\frac{b \left (1-c^2 x^2\right )^{3/2}}{9 c^5 d}-\frac{4 b \sqrt{1-c^2 x^2}}{3 c^5 d} \]
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Rubi [A] time = 0.237931, antiderivative size = 172, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {4715, 4657, 4181, 2279, 2391, 261, 266, 43} \[ \frac{i b \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{i b \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{2 i \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{c^5 d}+\frac{b \left (1-c^2 x^2\right )^{3/2}}{9 c^5 d}-\frac{4 b \sqrt{1-c^2 x^2}}{3 c^5 d} \]
Antiderivative was successfully verified.
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Rule 4715
Rule 4657
Rule 4181
Rule 2279
Rule 2391
Rule 261
Rule 266
Rule 43
Rubi steps
\begin{align*} \int \frac{x^4 \left (a+b \sin ^{-1}(c x)\right )}{d-c^2 d x^2} \, dx &=-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}+\frac{\int \frac{x^2 \left (a+b \sin ^{-1}(c x)\right )}{d-c^2 d x^2} \, dx}{c^2}+\frac{b \int \frac{x^3}{\sqrt{1-c^2 x^2}} \, dx}{3 c d}\\ &=-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}+\frac{\int \frac{a+b \sin ^{-1}(c x)}{d-c^2 d x^2} \, dx}{c^4}+\frac{b \int \frac{x}{\sqrt{1-c^2 x^2}} \, dx}{c^3 d}+\frac{b \operatorname{Subst}\left (\int \frac{x}{\sqrt{1-c^2 x}} \, dx,x,x^2\right )}{6 c d}\\ &=-\frac{b \sqrt{1-c^2 x^2}}{c^5 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}+\frac{\operatorname{Subst}\left (\int (a+b x) \sec (x) \, dx,x,\sin ^{-1}(c x)\right )}{c^5 d}+\frac{b \operatorname{Subst}\left (\int \left (\frac{1}{c^2 \sqrt{1-c^2 x}}-\frac{\sqrt{1-c^2 x}}{c^2}\right ) \, dx,x,x^2\right )}{6 c d}\\ &=-\frac{4 b \sqrt{1-c^2 x^2}}{3 c^5 d}+\frac{b \left (1-c^2 x^2\right )^{3/2}}{9 c^5 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}-\frac{2 i \left (a+b \sin ^{-1}(c x)\right ) \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{b \operatorname{Subst}\left (\int \log \left (1-i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{c^5 d}+\frac{b \operatorname{Subst}\left (\int \log \left (1+i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{c^5 d}\\ &=-\frac{4 b \sqrt{1-c^2 x^2}}{3 c^5 d}+\frac{b \left (1-c^2 x^2\right )^{3/2}}{9 c^5 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}-\frac{2 i \left (a+b \sin ^{-1}(c x)\right ) \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{c^5 d}+\frac{(i b) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{(i b) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{c^5 d}\\ &=-\frac{4 b \sqrt{1-c^2 x^2}}{3 c^5 d}+\frac{b \left (1-c^2 x^2\right )^{3/2}}{9 c^5 d}-\frac{x \left (a+b \sin ^{-1}(c x)\right )}{c^4 d}-\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{3 c^2 d}-\frac{2 i \left (a+b \sin ^{-1}(c x)\right ) \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{c^5 d}+\frac{i b \text{Li}_2\left (-i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}-\frac{i b \text{Li}_2\left (i e^{i \sin ^{-1}(c x)}\right )}{c^5 d}\\ \end{align*}
Mathematica [A] time = 0.304937, size = 286, normalized size = 1.66 \[ -\frac{-18 i b \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )+18 i b \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )+6 a c^3 x^3+18 a c x+9 a \log (1-c x)-9 a \log (c x+1)+2 b c^2 x^2 \sqrt{1-c^2 x^2}+22 b \sqrt{1-c^2 x^2}+6 b c^3 x^3 \sin ^{-1}(c x)+18 b c x \sin ^{-1}(c x)+9 i \pi b \sin ^{-1}(c x)-18 b \sin ^{-1}(c x) \log \left (1-i e^{i \sin ^{-1}(c x)}\right )-9 \pi b \log \left (1-i e^{i \sin ^{-1}(c x)}\right )+18 b \sin ^{-1}(c x) \log \left (1+i e^{i \sin ^{-1}(c x)}\right )-9 \pi b \log \left (1+i e^{i \sin ^{-1}(c x)}\right )+9 \pi b \log \left (\sin \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )+9 \pi b \log \left (-\cos \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )}{18 c^5 d} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.253, size = 270, normalized size = 1.6 \begin{align*} -{\frac{a{x}^{3}}{3\,{c}^{2}d}}-{\frac{ax}{{c}^{4}d}}-{\frac{a\ln \left ( cx-1 \right ) }{2\,{c}^{5}d}}+{\frac{a\ln \left ( cx+1 \right ) }{2\,{c}^{5}d}}-{\frac{b\arcsin \left ( cx \right ){x}^{3}}{3\,{c}^{2}d}}-{\frac{b\arcsin \left ( cx \right ) x}{{c}^{4}d}}-{\frac{ib}{{c}^{5}d}{\it dilog} \left ( 1-i \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \right ) }-{\frac{b{x}^{2}}{9\,{c}^{3}d}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{11\,b}{9\,{c}^{5}d}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{b\arcsin \left ( cx \right ) }{{c}^{5}d}\ln \left ( 1+i \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \right ) }+{\frac{b\arcsin \left ( cx \right ) }{{c}^{5}d}\ln \left ( 1-i \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \right ) }+{\frac{ib}{{c}^{5}d}{\it dilog} \left ( 1+i \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{6} \, a{\left (\frac{2 \,{\left (c^{2} x^{3} + 3 \, x\right )}}{c^{4} d} - \frac{3 \, \log \left (c x + 1\right )}{c^{5} d} + \frac{3 \, \log \left (c x - 1\right )}{c^{5} d}\right )} + \frac{-\frac{1}{3} \,{\left (c^{5} d{\left (\frac{2 \,{\left (c^{2} x^{2} + 2\right )} \sqrt{c x + 1} \sqrt{-c x + 1}}{c^{5} d} + \frac{18 \, \sqrt{c x + 1} \sqrt{-c x + 1}}{c^{5} d} + 3 \, \int -\frac{3 \, \sqrt{c x + 1} \sqrt{-c x + 1}{\left (\log \left (c x + 1\right ) - \log \left (-c x + 1\right )\right )}}{c^{6} d x^{2} - c^{4} d}\,{d x}\right )} + 6 \,{\left (c^{3} x^{3} + 3 \, c x\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) - 9 \, \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) \log \left (c x + 1\right ) + 9 \, \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) \log \left (-c x + 1\right )\right )} b}{6 \, c^{5} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{b x^{4} \arcsin \left (c x\right ) + a x^{4}}{c^{2} d x^{2} - d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \frac{\int \frac{a x^{4}}{c^{2} x^{2} - 1}\, dx + \int \frac{b x^{4} \operatorname{asin}{\left (c x \right )}}{c^{2} x^{2} - 1}\, dx}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (b \arcsin \left (c x\right ) + a\right )} x^{4}}{c^{2} d x^{2} - d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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